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Answer by Jack D'Aurizio for Improper integral over an open interval using...
The is nothing improper in the integral $\int_{0}^{1}\frac{\sin x}{x}\,dx$, since the function $f(x)=\frac{\sin x}{x}$ has a removable discontinuity at $x=0$, $\lim_{x\to 0}\frac{\sin...
View ArticleImproper integral over an open interval using the comparison test
I'm getting confused with improper integral over a closed interval it seems to me like the opposite of improper integrals when x tends to infinity.Example:$\int_0^1 \frac{sin^2x}{x^2}$I can see that...
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